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The equation for line p can be written as y= – 5/4 x–6. Line q includes the point (5, – 8) and is parallel to line p. What is the equation of line q?

Sagot :

rspill6

Answer:

y = -(5/4)x - (1 3/4)

Step-by-step explanation:

A line parallel to y= -(5/4)x - 6 will have the same slope, -(5/4), but a different value for the y-intercept, which is -6 in this equation.  This means we can write:

y = -(5/4)x + b

As klong a b is not -6, the line will be parallel.  But we are told that point (5,-8) must be on the new line.  That means we need to select a value of b to make that happen.  By shifting b, we can move the straight line up or down.  To move it so that it goes through (5,8), enter that point in the equation and solve for b:

y = -(5/4)x + b

-8 = -(5/4)*5 + b   for (5,-8)

-8 = -(25/4) + b

b = -8 + (25/4)

b = -(32/4)+(25/4)

b = -(7/4) or - 1 3/4

The parallel line that goes through (5,-8) is y = -(5/4)x - 2

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