darshansedai821
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the population of town increases by5℅ every year. In the last year, the population was 80,000. 1) find the present population 2) find the population of the town in the next two years.


explain step by step please​

Sagot :

Answer:

last year it was 80k

Step-by-step explanation:

Population increases by 5% every year

Last year it was 80,000

PRESENT POPULATION

Present population = 80,000 + 5% off 80,000

                               = 80,000 + 5/100 × 80,000

                               = 80,000 + 5 × 800

                               = 80,000 + 4,000

                               = 84,000

AFTER ONE YEAR

After this , the population again increases by 5%

Population = 84,000 + 5% off 84,000

                 = 84,000 + 5/100 × 84,000

                 = 84,000 + 5 × 840

                 = 84,000 + 4,200

                 = 88,200

ANSWERS

The population of present year is 84,000

After one year , the population becomes 88,200

Hope it helps :-)

Answer:

1. The Present population is 84,000

2. The next years population 88,200 and the year after that would be 92,610

Step-by-step explanation:

If you take the previous year and multiply it by 1.05 you you get the current population. After that you take the current population and multiply it again by 1.05 since the population increases by 5% so continue multiplying by 1.05 to get the later years and so forth

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