K1l31gh
Answered

Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

How many atoms of oxygen are contained in 160 grams of N203?

Sagot :

florida123465

Answer:

3.80 × 1024 grams containing

Explanation:

Step 1: calculate  the moles  of N2O3

moles= mass  N2O3 /molar mass N2O3

molar mass of N2O3 = (14  x2) +( 16 x3) =76 g/mol

moles of  N2O3  = 160 g/ 76 g/mol = 2.105  moles

Step 2:  from the  moles of N2O3 find the moles of Oxygen

=moles of N2O3   x number of oxygen atoms in N2O3( 3)

= 3 x 2.105  =6.315 moles

Step 3:use  the Avogadro's  law to calculate the atoms of oxygen

that is according to Avogadro's  law  1 mole =   6.02 x10 ^23 atoms

                                                              6.315 moles= ? atoms

={ (6.315 moles x 6.02 x10 ^23 atoms) / 1 mole}  =3.80  x10^24 atoms

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.