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How many atoms of oxygen are contained in 160 grams of N203?

Sagot :

florida123465

Answer:

3.80 × 1024 grams containing

Explanation:

Step 1: calculate  the moles  of N2O3

moles= mass  N2O3 /molar mass N2O3

molar mass of N2O3 = (14  x2) +( 16 x3) =76 g/mol

moles of  N2O3  = 160 g/ 76 g/mol = 2.105  moles

Step 2:  from the  moles of N2O3 find the moles of Oxygen

=moles of N2O3   x number of oxygen atoms in N2O3( 3)

= 3 x 2.105  =6.315 moles

Step 3:use  the Avogadro's  law to calculate the atoms of oxygen

that is according to Avogadro's  law  1 mole =   6.02 x10 ^23 atoms

                                                              6.315 moles= ? atoms

={ (6.315 moles x 6.02 x10 ^23 atoms) / 1 mole}  =3.80  x10^24 atoms

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