Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

If a reaction vessel initially contains an N2O4N2O4 concentration of 0. 0550 MM at 500 KK , what are the equilibrium concentrations of N2O4N2O4 and NO2NO2 at 500 KK

Sagot :

The concentration of NO2 is 0.054 M and that of N2O4 is 0.003 M.

Equilibrium constant

The equilibrium constant shows the extent to which reactants are converted into products.

We have the reaction;  N2O4⇌2NO2 and Kp = 4.5. Setting up the ICE table, we have;

       N2O4       ⇌     2NO2

I       0. 0550               0

C       -x                        +x

E    0. 0550 - x            x

Given that;

Kp = [NO2]^2/[N2O4]

4.5= (x)^2/0. 0550 - x

4.5(0. 0550 - x) = x^2

0.2475 - 4.5x = x^2

x^2 +  4.5x -  0.2475 = 0

x=0.054 M

The concentration of the required NO2 gas at equilibrium is 0.054 M and that of N2O4 is 0.003 M.

Learn more about equilibrium constant: https://brainly.com/question/17960050

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.