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what is the invers function of f(x)=(n+1)^3?

Sagot :

Answer:

[tex]f^{-1}(x)=\sqrt[3]{x}-1[/tex]

Step-by-step explanation:

[tex]f(x)=(x+1)^3\\\\y=(x+1)^3\\\\x=(y+1)^3\\\\\sqrt[3]{x}=y+1\\\\y=\sqrt[3]{x}-1\\ \\f^{-1}(x)=\sqrt[3]{x}-1[/tex]

Graphing both inverses, they will be symmetrical about the line [tex]y=x[/tex].

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