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Determine the slope of the line for the linear equation below. Show all work for
credit.
2/3 - 4y = 8

Sagot :

M=0
2/3-4y=8
Y=-11/6
Y=0x-11/6
M=0

Answer:

the slope is 0.

Explanation:

[tex]\hookrightarrow \sf \frac{2}{3} - 4y = 8[/tex]

[tex]\hookrightarrow \sf - 4y = 8- \frac{2}{3}[/tex]

[tex]\hookrightarrow \sf - 4y = \frac{24}{3} - \frac{2}{3}[/tex]

[tex]\hookrightarrow \sf - 4y = \frac{24-2}{3}[/tex]

[tex]\hookrightarrow \sf - 4y = \frac{22}{3}[/tex]

[tex]\hookrightarrow \sf y = \frac{22}{-12}[/tex]

[tex]\hookrightarrow \sf y = -\frac{11}{6}[/tex]

[tex]\hookrightarrow \sf y = -1\frac{5}{6}[/tex]

comparing with the formula: y =  mx + b

                               where m is slope and b is y-intercept.

we found that there is no x. so the value of slope will be 0x. slope = 0