Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

What mass of zinc will completely react with 125.0 mL of a solution of nitric acid (HNO3) which has concentration of 0.850M?

Sagot :

mickymike92

The mass of zinc required to react with HNO3 is 3.45 g

What is moles of HNO3 reacting?

The moles of HNO3 reacting is calculated using the formula below:

  • moles = concentration × volume

volume = 0.850

volume = 125.0 mL = 0.125 L

Moles of HNO3 = 0.850 × 0.125 = 0.10625 moles

Equation of reaction:

Zn + 2 HNO3 --> Zn(NO3)2 + H2

2 moles of HNO3 reacts with 1 mole of Zn.

moles of zinc reacting = 0.10625/2 = 0.053125

Mass of zinc = moles × molar mass

molar mass of Zn = 65

Mass of zinc = 0.053125 × 65

mass of Zn = 3.45 g

Therefore, the mass of zinc will completely react with 125.0 mL of a solution of nitric acid (HNO3) which has concentration of 0.850M is 3.45 g

Learn more about moles at: https://brainly.com/question/15356425

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.