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What mass of zinc will completely react with 125.0 mL of a solution of nitric acid (HNO3) which has concentration of 0.850M?

Sagot :

mickymike92

The mass of zinc required to react with HNO3 is 3.45 g

What is moles of HNO3 reacting?

The moles of HNO3 reacting is calculated using the formula below:

  • moles = concentration × volume

volume = 0.850

volume = 125.0 mL = 0.125 L

Moles of HNO3 = 0.850 × 0.125 = 0.10625 moles

Equation of reaction:

Zn + 2 HNO3 --> Zn(NO3)2 + H2

2 moles of HNO3 reacts with 1 mole of Zn.

moles of zinc reacting = 0.10625/2 = 0.053125

Mass of zinc = moles × molar mass

molar mass of Zn = 65

Mass of zinc = 0.053125 × 65

mass of Zn = 3.45 g

Therefore, the mass of zinc will completely react with 125.0 mL of a solution of nitric acid (HNO3) which has concentration of 0.850M is 3.45 g

Learn more about moles at: https://brainly.com/question/15356425

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