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Sagot :
In 58.2 grams of Na there is 1.51 x 10^24 atoms.
Mole calculation
To calculate the amount of atoms present in a mass sample, it is necessary to have knowledge of the molar mass of the element and Avogadro's constant, used in such a way that:
[tex]MM_Na= 23g/mol[/tex]
[tex]C = 6\times 10^{23}[/tex]
[tex]MM = \frac{m}{mol}[/tex]
[tex]23 = \frac{58.2}{x} = > 2.53 atoms[/tex]
Now, with the value of the number of moles, just calculate the number of atoms present, so that:
[tex]atoms = mol \times C[/tex]
[tex]atoms = 2.53 \times 6 \times 10^{23}[/tex]
[tex]atoms = 1.51 \times 10^{24}[/tex]
So, in 58.2 grams of Na there is 1.51 x 10^24 atoms.
Learn more about mole calculation in: brainly.com/question/2845237
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