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Sagot :
Answer:
the distance between city C and D is 7.6 inches
given:
- city A and city B is 8.5 inches, actually 5616 miles apart.
- city C and city D is x inches, actually 5041 miles apart
solving similarities:
[tex]\hookrightarrow \sf \dfrac{5616 }{8.5 } = \dfrac{5041 }{x}[/tex]
change sides
[tex]\hookrightarrow \sf 5616x = 5041(8.5)[/tex]
simplify
[tex]\hookrightarrow \sf 5616x = 42848.5[/tex]
change sides
[tex]\hookrightarrow \sf x = \dfrac{42848.5}{5616}[/tex]
simplify
[tex]\hookrightarrow \sf x = 7.62972[/tex]
rounded to nearest one decimal place
[tex]\hookrightarrow \sf x = 7.6[/tex]
Let that be x
- Ratio remains same
[tex]\\ \rm\bull\rightarrowtail \dfrac{8.5}{5616}=\dfrac{x}{5041}[/tex]
[tex]\\ \rm\bull\rightarrowtail 0.0015=\dfrac{x}{5041}[/tex]
[tex]\\ \rm\bull\rightarrowtail x=0.0015(5041)[/tex]
[tex]\\ \rm\bull\rightarrowtail x=7.6in[/tex]
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