calculates the speed of the satellite which performs orbital motion around the earth from an altitude of 3600km?

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02-03-2022
Physics

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calculates the speed of the satellite which performs orbital motion around the earth from an altitude of 3600km?

Sagot :

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the10legendgamer the10legendgamer · Answer 1 · 2022-03-02T15:24:24-05:00

the10legendgamer the10legendgamer

02-03-2022

Answer:

Using the equation for orbital speed

orbital speed= square root of GM/r

Where

G= Gravitational Constant = 6.674x10^-11m^3/kg.s^2

M= mass of The Earth=5.972x10^24 kg

r= the combined radius of The Earth and the height of the satellite above The Earth=6378km+ 3600km= 9978km converting to meters gives (1000m=1km) 9978km*1000m/1km= 9,978,000m or 9.978x10^6m

orbital speed = square root of (6.674x10^-11*5.972x10^24/9.978x10^6= 63198m/s

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