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Describe in detail an experiment using only hot and cold water that would enable you to
verify that the heat capacity of your coffee-cup calorimeter is about 1.0 x 10' J/°C. Be
specific about the procedure you would follow and the calculations you would need to
perform?

Sagot :

mickymike92

Based on the principle of conservation of energy, the heat capacity of the calorimeter is calculated using the formula:

  • c = {m2 × w × (t2 - t1) - m2 × w × (t2 -t1)}/m3 × (t2 -t1)

What is a calorimeter?

A calorimeter is an equipment used to determine heat of reaction.

The calorimeter works on the principle of conservation of energy:

  • heat gained = heat lost

Quantity of heat energy is calculated using the formula below:

  • q = mass × heat capacity × temperature difference

In the experiment, the following procedure is followed:

  • Mass of the hot water, cold water and calorimeter are recorded
  • temperature of the hot water is recorded
  • temperature of the the cold water and calorimeter is recorded
  • final temperature of the mixture is recorded
  • heat capacity of the calorimeter is calculated using the formula: heat gained by calorimeter and cold water = heat lost by hot water.

Assuming that;

  • mass of hot water = m1
  • mass of cold water =m2
  • mass of calorimeter = m3
  • initial temperature cold water and calorimeter = t1
  • final temperature of mixture = t2
  • heat capacity of water = w
  • heat capacity of calorimeter = c

Therefore, the heat capacity of the calorimeter is calculated using the formula:

  • c = {m2 × w × (t2 - t1) - m2 × w × (t2 -t1)}/m3 × (t2 -t1)

Learn more about calorimeters at: https://brainly.com/question/1407669

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