Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Reaction
SiCl₄+ 2Mg ⇒ Si + 2MgCl₂
to find limiting reagents: divide the number of moles by their coefficients
SiCl₄ = 1 mole : 1 (coefficient) = 1
Mg = 5 mole : 2 (coefficient) = 2.5
SiCl₄ as a limiting reactant (smaller), and Mg as an excess
then all the compounds involved in the reaction are based on moles of SiCl₄
Si produced =
[tex]\tt \dfrac{coefficient~Si}{coefficient~SiCl_4}\times mole~Si=\dfrac{1}{1}\times 1=1[/tex]
Reacted Mg (excess) = 2/1 x 1 = 2 mole
mole Mg remaining = 5 - 2 = 3 mole
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.