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A troupe of 8 dancers is going to line up on stage. Of these dancers, 4 are wearing black and 4 are wearing red. A dancer wearing black must be in the first position and they must alternate between colors. In how many ways can the dancers line up?

Sagot :

Using the Fundamental Counting Theorem, it is found that there are 576 ways for the dancers to line up.

What is the Fundamental Counting Theorem?

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem, considering the order:

Black - Red - Black - Red - Black - Red - Black - Red

The number of ways for each is given by:

4 - 4 - 3 - 3 - 2 - 2 - 1 - 2

Hence:

[tex]N = 4^2 \times 3^2 \times 2^2 = 576[/tex]

There are 576 ways for the dancers to line up.

To learn more about the Fundamental Counting Theorem, you can check https://brainly.com/question/24314866

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