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Find the 12th term of the arithmetic sequence x−4, 3x−11, 5x-18, ...

Sagot :

devishri1977

Answer:

Step-by-step explanation:

x -4  , 3x-11 , 5x - 18 ,.......

first term = a = x -4

Common difference (d) = second term  - first term

                                =  3x -11 - [ x - 4]

                                = 3x - 11 - x + 4

                                = 3x - x - 11 + 4

                                 = 2x - 7

nth term = a + (n-1)*d

12th term = x - 4 + 11*(2x - 7)

               = x - 4 + 11*2x  - 7 *11

                = x - 4 + 22x - 77

                =x + 22x - 4 - 77

                = 23x - 81

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