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One factor of the function f(x) = x3 − 6x2 + 11x − 6 is (x − 3)

Find the x-intercepts and the y-intercept of the graph of f(x) without using technology

real confused on this one! please help!!!


Sagot :

Let f(x)= y = x3 - 6x2 + 11x - 6
X intercept means a point on the graph which intercepts the x axis
And Y-intercept mean a point on the graph which intercepts the y axis
Meaning at the x intercept the component of y is zero because there is no y on the x axis


And at the y intercept the x component of the coordinate is zero because on the y axis there is no x value
So in finding the y intercept of the graph wherever u see x place zero there (ie x= 0 on the y axis)
So with x = 0
y = (0)3- 6(0)2 + 11(0) - 6
y = -6

Therefore the y intercept is (0,-6) in coordinate form or -6

X-intercept
y = x3 - 6x2 + 11x - 6
After factorization and simplification
y = (x-1)(x-2)(x-3)
On the x axis y= 0
0= (x-1)(x-2)(x-3)
Either x-1=0
x=1
(1,0)
Or x-2=0
x=2
(2,0)
Or x-3=0
x=3 (3,0)
Therefore the x intercepts are 1,2 and 3
And they are expressed in coordinate form as (1,0) ,(2,0) and
(3,0)