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What is the equation of the line that passes through the point (1,8) and has a slope of 11?

Sagot :

reinhard10158

Step-by-step explanation:

the easiest approach for a given point and slope of the line is the point-slope form

y - y1 = a(x - x1)

with "a" being the slope, and (x1, y1) being a point on the line.

so, we get

y - 8 = 11(x - 1)

if we need the slope-intercept form

y = ax + b

we simplify the point-slope form

y - 8 = 11x - 11

y = 11x - 3

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