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Sagot :
- radius=r=2in
Volume:-
[tex]\\ \rm\Rrightarrow V=\dfrac{4}{3}\pi r^3[/tex]
[tex]\\ \rm\Rrightarrow V=\dfrac{4}{3}\pi (2)^3[/tex]
[tex]\\ \rm\Rrightarrow V=\dfrac{32\pi}{3}in^3[/tex]
Half volume:-
[tex]\\ \rm\Rrightarrow V=\dfrac{16\pi}{3}in^3[/tex]
Answer:
16.8 in³ (nearest tenth)
Step-by-step explanation:
Volume of a sphere
[tex]V=\dfrac43 \pi r^3[/tex]
(where V is volume and r is the radius)
Volume of a hemisphere
[tex]\textsf{Volume of a hemisphere}=\dfrac12 \ \textsf{Volume of a Sphere}[/tex]
[tex]\implies V=\dfrac12 \cdot \dfrac43 \pi r^3=\dfrac23 \pi r^3[/tex]
Given:
- r = 2 in
[tex]\begin{aligned}\implies V & =\dfrac23 \pi (2)^3\\\\ & =\dfrac{16}{3} \pi\\\\ & =16.8 \ \sf in^3 \ (nearest \ tenth)\end{aligned}[/tex]
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