Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
- radius=r=2in
Volume:-
[tex]\\ \rm\Rrightarrow V=\dfrac{4}{3}\pi r^3[/tex]
[tex]\\ \rm\Rrightarrow V=\dfrac{4}{3}\pi (2)^3[/tex]
[tex]\\ \rm\Rrightarrow V=\dfrac{32\pi}{3}in^3[/tex]
Half volume:-
[tex]\\ \rm\Rrightarrow V=\dfrac{16\pi}{3}in^3[/tex]
Answer:
16.8 in³ (nearest tenth)
Step-by-step explanation:
Volume of a sphere
[tex]V=\dfrac43 \pi r^3[/tex]
(where V is volume and r is the radius)
Volume of a hemisphere
[tex]\textsf{Volume of a hemisphere}=\dfrac12 \ \textsf{Volume of a Sphere}[/tex]
[tex]\implies V=\dfrac12 \cdot \dfrac43 \pi r^3=\dfrac23 \pi r^3[/tex]
Given:
- r = 2 in
[tex]\begin{aligned}\implies V & =\dfrac23 \pi (2)^3\\\\ & =\dfrac{16}{3} \pi\\\\ & =16.8 \ \sf in^3 \ (nearest \ tenth)\end{aligned}[/tex]
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.