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How do you solve 2x-3y=-4 and x=7-3y by substitution?

Sagot :

iciclepiano18

Answer:

[tex](1, 2)[/tex]

Step-by-step explanation:

We can solve this system using substitution.

In this case, we can substitute 7-3y for x, as they are of equal value.

Therefore...

[tex]2x-3y=-4\\2(7-3y)-3y=-4\\14-6y-3y=-4\\14-9y=-4[/tex]

Subtract 14 from both sides:

[tex]-9y=-18[/tex]

Divide both sides by -9

[tex]y=2[/tex]

Now, substitute 2 for y to solve for x:

[tex]x=7-3y=7-3(2)=7-6=1[/tex]

Therefore the solution to this system of equations is:

[tex](x, y)=(1, 2)[/tex]

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