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A line pass through 1,-5 and the slope of 9

Sagot :

Answer: y = 9x - 14

Step-by-step explanation:

The equation of a line is y = mx + b

We know the slope is 9 so so far the equation we have is y = 9x + b.

Since we know (1,-5) is a point on the line, we can plug in the x and y values into the equation and we get:

-5 = 1*9 + b

-5 = 9 + b

b = -14.

Therefore, the equation of the line is y = 9x - 14

Hello.

Here we have a point that the line passes through: (1, -5)

We also have the line's slope: 9

Now, we have enough information to write the line's equation in Point-Slope Form:

[tex]\mathrm{y-y1=m(x-x1)}[/tex]

Plug in the values and solve:

[tex]\mathrm{y-(-5)=9(x-1)}[/tex]

[tex]\mathrm{y+5+9(x-1)}[/tex]

[tex]\mathrm{y+5=9x-9}[/tex]

[tex]\mathrm{y=9x-9-5}[/tex]

[tex]\mathrm{y=9x-14}[/tex]

Therefore, the answer is

[tex]\mathrm{y=9x-14}[/tex]

I hope it helps.

Have a nice day.

[tex]\boxed{imperturbability}[/tex]