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A 96cm A long wire is given the shape of a rectangle such that its length is 12 cm more than its breadth Find the dimensions of the rectangle.​

Sagot :

Answer:

The length of the rectangle is 30 cm, and the width of the rectangle is 18 cm.

Step-by-step explanation:

Since the wire is shaped as a rectangle, and we need perimeter for this problem, we can use the equation (l+w)*2, and the perimeter is 96, where l is the length and w is the width.

Since the length is 12 cm longer than the width, then we have:

W + 12 = L

Now substitute for the L in our equation and solve.

(w+12+w)*2 = 96

(2w + 12) *2 = 96

Multiply using the distributive property

4w + 24 = 96

4w = 72

w = 18

Now plug in the w for our second equation:

18 + 12 = L

30 = L

Now check our answer by plugging it in our old equation:

(18+30)*2 = 96

48*2 = 96

96 = 96

Our answer is correct, so the length of the rectangle is 30 cm, and the width of the rectangle is 18 cm. Hope this helps.

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