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Order the real numbers from greatest (top) to least (bottom)

Order The Real Numbers From Greatest Top To Least Bottom class=

Sagot :

[tex]\sqrt[3]{102} = 4.672\\6.5\\\frac{69}{25} =2.76\\\sqrt{102} = 10.0995[/tex]

Thus the numbers from greatest to least is

    [tex]\sqrt{102}, 6\frac{1}{2} ,\sqrt[3]{102} , \frac{69}{25}[/tex]

Hope that helps!

Answer:

[tex]\sqrt{102} > 6\frac{1}{2} > \sqrt[\frac{1}{3}]{102} > \frac{69}{25}[/tex]

Step-by-step explanation:

[tex]4 < \sqrt[3]{102} < 5[/tex]          [tex]\left\{\sqrt{64}=4,\sqrt[7]{125}=5\right\}[/tex]

[tex]6\frac{1}{2}=6.5[/tex]

[tex]\frac{69}{25}=2.76[/tex]

[tex]10 < \sqrt{102} < 11[/tex]          [tex]\left\{\sqrt{100}=10\sqrt{121}=11\right\}[/tex]

So from greater to least:

[tex]\sqrt{102} > 6\frac{1}{2} > \sqrt[\frac{1}{3}]{102} > \frac{69}{25}[/tex]

I hope this helps you

:)

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