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Find the area of the iscoselies triangle when the base is 10cm and hypotenuse is 13

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evelynimafidon2

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please give brainliest

Step-by-step explanation:

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Answer:

[tex]\sf\: Area \: of \: the \: triangle \: = \boxed{\boxed{\bf\:50 \: cm^{2}}}[/tex]

Step-by-step explanation:

Given,

The triangle is an isosceles triangle.

  • Base (b) = 10 cm
  • Hypotenuse = 13 cm
  • Altitude (h) = Base = 10 cm [isosceles triangle has equal opposite sides]

Since, we are given the hypotenuse, the triangle will be an isosceles right angled triangle.

We know that, area of a right angled triangle = ½ × b × h

By substituting the values in the above formula...

½ × b × h

= ½ × 10 × 10

= ½ × 100

= [tex]\boxed{\boxed{\bf\:50 \: cm^{2}}}[/tex]

______________

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