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What is the solution to log[sub=2]9x-log[sub=2]^3=3
x = three-eighths
x = eight-thirds
x = 3
x = 9

What Is The Solution To Logsub29xlogsub233 X Threeeighths X Eightthirds X 3 X 9 class=

Sagot :

Anonimity

Step-by-step explanation:

[tex]\begin{aligned}\log_2(9x)-\log_2(3)&=3\\\log_2\left(\frac{9x}{3}\right)&=3\\\log_2(3x)&=\log_2(2^3)\\3x&=2^3\\3x&=8\\x&=\frac{8}{3}\end{aligned}[/tex]

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