Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

If a coin is tossed 4 times, and then a standard six-sided die is rolled 4 times, and finally a group of three cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?

Sagot :

nevaehharris46

Answer there are 3 outcomes

Step-by-step explanation:

Answer:

89,820,057,600.

Step-by-step explanation:

For the number of ways 5 cards can be taken from a standard 52 card deck, there are 52 choices for the first card. After the first card is chosen, there are 51 choices remaining for the second card. Following this pattern, you will the total number of ways the 5 cards can be chosen being 52 x 51 x 50 x 49 x 48 = 311,875,200. Or, you can also use the permutation of 52 cards taken 5 at a time which is 52!/(52 – 5)! = 311,875,200.

Hence, the total number of outcomes for all the above is 8 x 36 x 311,875,200 = 89,820,057,600.

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.