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Sagot :
*Note that:
[tex] \boxed{ \sf \: area \: of \: rectangle = length \times breadth}[/tex]
Now,
- Length = 2/3 (Given)
- Width = 3/4 (Given)
Solve ;
[tex] \tt \implies \: area = \frac{2}{3} \times \frac{3}{4} [/tex]
[tex] \tt \implies \: area = \frac{2 \times 3}{3 \times 4} [/tex]
[tex] \tt \implies \: area = \frac{6}{12} = \frac{1}{2} [/tex]
➪ Thus, The carpet takes up 1/2 unit² area of the classroom...~
Answer:
1/2 or half of the classroom area
Step-by-step explanation:
Step 1: Calculating area of carpet
Let total length be l and width be w.
Now, according to the problem,
Area = 2l/3 x 3w/4
= 2lw/4
Step 2: Take area of carpet and area of classroom as a ratio
(2lw/4) / lw
= 2/4
= 1/2
Therefore, the carpet takes up 1/2 or half of the classroom area.
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