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Sagot :
The current flowing in each resistor of the circuit is 4 A.
Equivalent resistance of the series resistors
The equivalent resistance of the series circuit is calculated as follows;
6 Ω and 4 Ω are in series = 10 Ω
5 Ω and 10Ω are in series = 15 Ω
Effective resistance of the circuit
[tex]\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \\\\R = \frac{R_1R_2}{R_1 + R_2} \\\\R = \frac{10 \times 15}{10 + 15} \\\\R = 6 \ ohms[/tex]
Current flowing in the circuit
V = IR
I = V/R
I = 24/6
I = 4 A
Learn more about resistors in parallel here: https://brainly.com/question/15121871
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