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For the circuit shown in the figure(figure 1) find the current through each resistor. Express your answers using two significant figures. Enter your answers numerically separated by commas.

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onyebuchinnaji

The current flowing in each resistor of the circuit is 4 A.

Equivalent resistance of the series resistors

The equivalent resistance of the series circuit is calculated as follows;

6 Ω and 4 Ω are in series = 10 Ω

5 Ω and 10Ω are in series = 15 Ω

Effective resistance of the circuit

[tex]\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \\\\R = \frac{R_1R_2}{R_1 + R_2} \\\\R = \frac{10 \times 15}{10 + 15} \\\\R = 6 \ ohms[/tex]

Current flowing in the circuit

V = IR

I = V/R

I = 24/6

I = 4 A

Learn more about resistors in parallel here: https://brainly.com/question/15121871

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