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Answer this question 4 me please

Answer This Question 4 Me Please class=

Sagot :

Snor1ax

Answer: C

Step-by-step explanation:

To Ax^2+Bx+C=0 form (add 2 to both sides):

[tex]2y^2-5y+2=0[/tex]

Use the quadratic formula (a = 2, b=-5, c= 2)

[tex]y=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\cdot \:2}}{2\cdot \:2}[/tex]

[tex]y=\frac{-\left(-5\right)\pm \:3}{2\cdot \:2}[/tex]

[tex]y=\frac{-\left(-5\right)+3}{2\cdot \:2},\:y_2=\frac{-\left(-5\right)-3}{2\cdot \:2}[/tex]

[tex]y_{1}=2,\:\\y_{2}=\frac{1}{2}[/tex]

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