Answered

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2. A 6 kg object is initially at rest. A 300 N force acts on the object, moving it forward 4 meters in
2 seconds.
a) How much work does the force do on the object?
b) How much power is exerted on the object?
c) What is the final velocity of the object?

Sagot :

Answer: a. 1200J b. 600W c. 20m/s

Explanation: W = Fxcos

F = 300, x=4, direction of force is = to direction of object so cos(0) = 1

a) 300*4 = 1200

b) P = W/t

1200/2 = 600W

c) vf^2 = vi^2 + 2ax

vi = 0, x = 4, a= 300/6

vf^2 = 2(50)(4)

vf^2 = 400

vf= 20m/s

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