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solve trigonometric function
cot0/tan0

Sagot :

semsee45

Answer:

[tex]\dfrac{1}{\tan^2(\theta)}}=\cot^2(\theta)[/tex]

Step-by-step explanation:

[tex]\cot(\theta)=\dfrac{1}{\tan(\theta)}[/tex]

[tex]\implies \dfrac{\cot(\theta)}{\tan(\theta)}=\dfrac{1}{\tan(\theta)}\div{\tan(\theta)}}=\dfrac{1}{\tan(\theta)} \times \dfrac{1}{\tan(\theta)} =\dfrac{1}{\tan^2(\theta)}}=\cot^2(\theta)[/tex]

[tex]\\ \rm\Rrightarrow cotA\div tanA[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{cosA}{sinA}\div \dfrac{sinA}{cosA}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{cosA}{sinA}\times \dfrac{cosA}{sinA}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{cos^2A}{sin^2A}[/tex]

[tex]\\ \rm\Rrightarrow cot^2A[/tex]

Note

  • theta is taken as A
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