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There are 6 members of the student council and there are 10 chairs in their meeting room. If all 6 members
attend a meeting, how many different seating arrangements are possible?

Sagot :

The number of different seating arrangements is an illustration of permutation

There are 151200 different seating arrangements

How to determine the number of sitting arrangements

The number of seats (n) is given as:

n = 10

The number of people (r) is given as:

r = 6

So, the number of seating arrangements is:

[tex]^nP_r = \frac{n!}{(n - r)!}[/tex]

This gives

[tex]^{10}P_6 = \frac{10!}{(10 - 6)!}[/tex]

Simplify

[tex]^{10}P_6 = \frac{10!}{4!}[/tex]

Evaluate the quotient

[tex]^{10}P_6 = 151200[/tex]

Hence, there are 151200 different seating arrangements

Read more about permutation at:

https://brainly.com/question/12468032