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Sagot :
The athlete must leave the ground with a speed of 6.33m/s.
Kinect and potential energy
To calculate the initial speed, with the information of height and final speed, we can use the following expression that uses the kinetic energy and potential energy:
[tex]mgh_1 + \frac{1}{2}mv_1^{2}= mgh_2 + \frac{1}{2}mv_2^{2}[/tex]
Applying the values given by the statement we have:
[tex]9.81\times 0 + \frac{1}{2}v_1^{2} = 9.81 \times 2 + \frac{1}{2}(0.95)^{2}[/tex]
[tex]v_1 = 6.33m/s[/tex]
So, the athlete must leave the ground with a speed of 6.33m/s.
Learn more about kinect and potential energy in: brainly.com/question/14509624
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