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W(OH)2 + 2 HCl → WCl2 + 2 H2O

How many grams of W(OH)2 are needed to react with 150 grams of HCl?

(MM W(OH)2 = 217.855 g/mol) (MM HCl = 36.461 g/mol)

Group of answer choices

448.126 grams HCl

50.209 grams HCl

50.209 grams W(OH)2

448.126 grams W(OH)2

Sagot :

Oseni

The amount of W(OH)2 needed would be 448.126 g

Stoichiometric calculation

From the equation of the reaction:

W(OH)2 + 2 HCl → WCl2 + 2 H2O

The mole ratio of W(OH)2 to HCl is 1:2

Mole of 150g HCl = 150/36.461

                                 = 4.11 moles

Equivalent mole of W(OH)2 = 4.11/2

                                           = 2.06 moles

Mass of 2.06 moles W(OH)2 = 2.06 x 217.855

                                                = 448.188g

More on stoichiometric calculations can be found here: https://brainly.com/question/8062886

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