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Help please Im giving brianless and 100 points to the person who answer and show their work thank you very much


Help Please Im Giving Brianless And 100 Points To The Person Who Answer And Show Their Work Thank You Very Much class=

Sagot :

Answer:

8.5 ft (nearest tenth)

Step-by-step explanation:

To find the depth of the pool at the deep end, we need to find the height of the right triangle with angle 16.5° and add it to 4.5 ft

Base of the triangle = 35 - 9 - 12.5 = 13.5 ft

Use the tan trig ratio:

[tex]\tan(x)=\dfrac{O}{A}[/tex]

where x is the angle, O is the side opposite and angle and A is the side adjacent to the angle in a right triangle.

Given:

  • x = 16.5°
  • O = h (height)
  • A = 13.5 ft

[tex]\implies\tan(16.5)=\dfrac{h}{13.5}\\\\\implies h= 13.5\tan(16.5)\\\\\implies h = 4.0 \textsf{ ft (nearest tenth)}[/tex]

Therefore, the depth of the pool at the deepest end = 4 + 4.5 = 8.5 ft (nearest tenth)

  • Base=35-9-12.5=12.5ft=B
  • Perpendicular=p
  • \theta= 16.5°

Now

[tex]\\ \rm\Rrightarrow tan\theta=\dfrac{P}{B}[/tex]

[tex]\\ \rm\Rrightarrow tan16.5=\dfrac{P}{13.5}[/tex]

[tex]\\ \rm\Rrightarrow P=13.5tan16.5[/tex]

[tex]\\ \rm\Rrightarrow P=13.5(0.3)[/tex]

[tex]\\ \rm\Rrightarrow P\approx 4ft[/tex]