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Sagot :
Answer:
8.5 ft (nearest tenth)
Step-by-step explanation:
To find the depth of the pool at the deep end, we need to find the height of the right triangle with angle 16.5° and add it to 4.5 ft
Base of the triangle = 35 - 9 - 12.5 = 13.5 ft
Use the tan trig ratio:
[tex]\tan(x)=\dfrac{O}{A}[/tex]
where x is the angle, O is the side opposite and angle and A is the side adjacent to the angle in a right triangle.
Given:
- x = 16.5°
- O = h (height)
- A = 13.5 ft
[tex]\implies\tan(16.5)=\dfrac{h}{13.5}\\\\\implies h= 13.5\tan(16.5)\\\\\implies h = 4.0 \textsf{ ft (nearest tenth)}[/tex]
Therefore, the depth of the pool at the deepest end = 4 + 4.5 = 8.5 ft (nearest tenth)
- Base=35-9-12.5=12.5ft=B
- Perpendicular=p
- \theta= 16.5°
Now
[tex]\\ \rm\Rrightarrow tan\theta=\dfrac{P}{B}[/tex]
[tex]\\ \rm\Rrightarrow tan16.5=\dfrac{P}{13.5}[/tex]
[tex]\\ \rm\Rrightarrow P=13.5tan16.5[/tex]
[tex]\\ \rm\Rrightarrow P=13.5(0.3)[/tex]
[tex]\\ \rm\Rrightarrow P\approx 4ft[/tex]
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