Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Answer:
8.5 ft (nearest tenth)
Step-by-step explanation:
To find the depth of the pool at the deep end, we need to find the height of the right triangle with angle 16.5° and add it to 4.5 ft
Base of the triangle = 35 - 9 - 12.5 = 13.5 ft
Use the tan trig ratio:
[tex]\tan(x)=\dfrac{O}{A}[/tex]
where x is the angle, O is the side opposite and angle and A is the side adjacent to the angle in a right triangle.
Given:
- x = 16.5°
- O = h (height)
- A = 13.5 ft
[tex]\implies\tan(16.5)=\dfrac{h}{13.5}\\\\\implies h= 13.5\tan(16.5)\\\\\implies h = 4.0 \textsf{ ft (nearest tenth)}[/tex]
Therefore, the depth of the pool at the deepest end = 4 + 4.5 = 8.5 ft (nearest tenth)
- Base=35-9-12.5=12.5ft=B
- Perpendicular=p
- \theta= 16.5°
Now
[tex]\\ \rm\Rrightarrow tan\theta=\dfrac{P}{B}[/tex]
[tex]\\ \rm\Rrightarrow tan16.5=\dfrac{P}{13.5}[/tex]
[tex]\\ \rm\Rrightarrow P=13.5tan16.5[/tex]
[tex]\\ \rm\Rrightarrow P=13.5(0.3)[/tex]
[tex]\\ \rm\Rrightarrow P\approx 4ft[/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.