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Sagot :
Answer:
volume of a cylinder = [tex]\pi r^2h[/tex] (where r is the radius and h is the height)
diameter = [tex]2r[/tex] (where r is the radius)
A) volume of Cup A = [tex]\pi \times 5^2\times20=500\pi \textsf{ cm}^3[/tex]
B) Assuming the volume of the punch bowl is [tex]\dfrac{130000}{3}\pi \textsf{ cm}^3[/tex]
[tex]\implies \dfrac{130000}{3}\pi \div 500\pi=\dfrac{260}{3}=87 \textsf{ (nearest whole number)}[/tex]
C) volume of Cup B = [tex]\pi \times 10^2\times20=2000\pi\textsf{ cm}^3[/tex]
D) Assuming the volume of the punch bowl is [tex]\dfrac{130000}{3}\pi \textsf{ cm}^3[/tex]
[tex]\implies \dfrac{130000}{3}\pi \div 2000\pi=\dfrac{65}{3}=22 \textsf{ (nearest whole number)}[/tex]
#1
Diameter=10cm
- Radius=r=5cm
- Height=20cm=h
[tex]\\ \rm\Rrightarrow V=\pi r^2h[/tex]
[tex]\\ \rm\Rrightarrow V=\pi 25(20)[/tex]
[tex]\\ \rm\Rrightarrow V=500\pi cm^3[/tex]
#2
Total cups:-
- 130000/3π÷500π =87cups
#3
- Radius=r=10cm
- Height=20cm
[tex]\\ \rm\Rrightarrow V=\pi 100(20)[/tex]
[tex]\\ \rm\Rrightarrow V=2000\pi cm^3[/tex]
#4
Total cups
- 130000/3 π÷2000π=22cups
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