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Sagot :
Step-by-step explanation:
Formula:
[tex]\boxed{a = 3.14(r)^{2} }[/tex]
r represents the radius.
The radius is 1/2 of the diameter.
Since 1/2 of 16 is 8, 8 is our radius.
Substitute:
[tex]a = 3.14(8)^{2} [/tex]
Solve:
[tex]a = 3.14(64)[/tex]
[tex]a = 200.96in^{2} [/tex]
16:2 because that gives the radius
are of a circle= πr2
so you substitute in
r=8^2 =64
π=3.14
A=64x3.14
A=200.96
are of a circle= πr2
so you substitute in
r=8^2 =64
π=3.14
A=64x3.14
A=200.96
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