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Slope-intercept form
Linear equations are often organized in slope-intercept form:
[tex]y=mx+b[/tex]
- (x,y) = a point that falls on the line
- m = the slope of the line
- b = the y-intercept of the line
Slope (m)
The slope of a line is equal to its [tex]\dfrac{rise}{run}[/tex].
- "Rise" refers to the number of units the line travels up.
- "Run" refers to the number of units the line travels to the right.
Typically, we would solve for the slope by using the following formula:
- [tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Y-intercept (b)
The y-intercept of a line refers to the y-value that occurs when x=0.
On a graph, it is the y-value where the line crosses the y-axis.
Writing the Equation
1) Determine the slope of the line (m)
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
Plug in the two given points, (-17,-4) and (-7,-13):
[tex]m=\dfrac{-13-(-4)}{(-7)-(-17)}\\\\m=\dfrac{-13+4}{-7+17}\\\\m=\dfrac{-9}{10}[/tex]
Therefore, the slope of the line is [tex]-\dfrac{9}{10}[/tex]. Plug this into [tex]y=mx+b[/tex]:
[tex]y=-\dfrac{9}{10}x+b[/tex]
2) Determining the y-intercept (b)
[tex]y=-\dfrac{9}{10}x+b[/tex]
Plug in one of the given points and solve for b:
[tex]-4=-\dfrac{9}{10}(-17)+b\\\\-4=\dfrac{153}{10}+b\\\\b=-\dfrac{193}{10}[/tex]
Therefore, the y-intercept of the line is [tex]-\dfrac{193}{10}[/tex]. Plug this back into our equation:
[tex]y=-\dfrac{9}{10}x-\dfrac{193}{10}[/tex]
Answer
[tex]y=-\dfrac{9}{10}x-\dfrac{193}{10}[/tex]
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