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A bag contains 4 blue marbles and 3 yellow marbles. what is the probability of drawing a blue marbles followed by a green marbles, with replacing the first marble before drawing the second marbles.


Sagot :

Answer:

Too complex to understand the question

"with replacing the first marble before drawing the second marbles"????

Step-by-step explanation:

Answer:

12/49

Step-by-step explanation:

Base on the given:

4 Blue marbles

3 Green marbles

Total - 7 marbles

To Find:

what is the probability of drawing a blue marbles followed by a green marbles, with replacing the first marble before drawing the second marbles.

Note:

Followed by = Multiply

Solve:

4/7 × 3/7

= 12/49

Hence, the  probability of drawing a blue marbles followed by a green marbles, with replacing the first marble before drawing the second marbles is 12/49

Kavinsky

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