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You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the empirical formula of this compound?

Sagot :

The empirical formula of this compound is [tex]Fe_2O_3[/tex]

Empirical formula

To calculate the empirical formula of a compound, the value of moles of each element is needed.

As we have the information of the mass value, we will use the molar mass expression, which corresponds to:

[tex]MM_O = 16g/mol\\MM_Fe = 55.8g/mol[/tex]

                                              [tex]MM = \frac{m}{mol}[/tex]

  • O

                                                   [tex]16 = \frac{4.8}{x}[/tex]

                                                   [tex]x = 0.3mol[/tex]

  • Fe

                                                    [tex]55.8=\frac{11.2}{x}\\x = 0.2[/tex]

As the value of the empirical formula must be an integer, simply multiply the two values ​​by a common factor:

                                                [tex]O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2[/tex]

                                                       [tex]Fe_2O_3[/tex]

So, the empirical formula of this compound is [tex]Fe_2O_3[/tex].

Learn more about empirical formula: brainly.com/question/1247523