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Sagot :

boatengalbert291
Considering the volume of the cone (V1)
V1=1/3 x π x r2 x h
=1/3 x π x(6/2)^2 x 8
=75.4 in3

Considering the volume of the cylinder
V2 = πr2 x h
= π x (6/2)^2 x 8
=226.2 in3

Difference in volume
= V2 - V1
= 226.2 -75.4
= 150.8
≈ 151 in3
Hence the closest difference is 151 in3
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