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Sagot :
A. The mole fraction of isopropanol in the solution is 0.124
B. The mass percent of isopropanol is 12.4%
C. The molality of isopropanol is 7.86 M
A. How to determine the mole fraction of isopropanol
- Mole of isopropanol = 0.470 mole
- Mole of water = 3.320 mole
- Total mole = 0.470 + 3.32 = 3.79 mole
- Mole fraction of isopropanol =?
Mole fraction = mole / total mole
Mole fraction of isopropanol = 0.470 / 3.79
Mole fraction of isopropanol = 0.124
B. How to determine the percentage of isopropanol
- Mole of isopropanol = 0.470 mole
- Total mole = 3.79 mole
- Percentage of isopropanol =?
Percentage = (mole / total mole) × 100
Percentage of isopropanol = (0.470 / 3.79) × 100
Percentage of isopropanol = 12.4%
C. How to determine the molality
- Mole of isopropanol = 0.470 mole
- Mole of water = 3.320 mole
- Mass of water = 3.320 × 18 = 59.76 g = 59.76 / 1000 = 0.05976 Kg
- Molality of isopropanol =?
Molality = mole / Kg of water
Molality of isopropanol = 0.47 / 0.05976
Molality of isopropanol = 7.86 M
Learn more about Molality:
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