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A 5.5 × 10–3 M solution of fluoroacetic acid, CH2FCOOH, has a pH of 2.57. What is the acid-dissociation constant, K a, of this acid?

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The acid dissociation constant is 1.3 × 10^-3.

What is acid-dissociation constant?

The acid-dissociation constant is a constant that shows the extent of dissociation of an acid in solution. We have to set up the reaction equation as shown below;

Let the acid be HA;

                  HA       +      H2O ⇄      H3O^+      +      A^-

since the pH of the solution is 2.57 then;

[H3O^+] = Antilog(-pH) = Antilog(-2.57) = 2.7 × 10^-3

We can see that; [H3O^+]  = [A^-] so;

Ka = (2.7 × 10^-3)^2/(5.5 × 10^–3)

Ka = 1.3 × 10^-3

Learn more about acid-dissociation constant: https://brainly.com/question/9728159

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