Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Find the derivative of the function below in two ways. F(x) = x − 5x x x (a) by using the Quotient Rule F'(x) = (b) by simplifying first F'(x) = (c) Which method appears to be simpler for this problem? the Quotient Rule simplifying first

Sagot :

Space

Answer:

(a)  [tex]\displaystyle F'(x) = \frac{1}{2\sqrt{x}} - 5[/tex]

(b)  [tex]\displaystyle F'(x) = \frac{1}{2\sqrt{x}} - 5[/tex]

(c)  Simplifying first

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                          [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                        [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                            [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Quotient Rule]:                                                                          [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle F(x) = \frac{x - 5x\sqrt{x}}{\sqrt{x}}[/tex]

Step 2: Differentiate Way 1

  1. Derivative Rule [Quotient Rule]:                                                                  [tex]\displaystyle F'(x) = \frac{\sqrt{x} \big( x - 5x\sqrt{x} \big) ' - \big( \sqrt{x} \big) ' \big( x - 5x\sqrt{x} \big) }{\big( \sqrt{x} \big) ^2}[/tex]
  2. Rewrite [Derivative Property - Addition/Subtraction]:                               [tex]\displaystyle F'(x) = \frac{\sqrt{x} \Big[ \big( x \big) '- \big( 5x\sqrt{x} \big) ' \Big] - \big( \sqrt{x} \big) ' \big( x - 5x\sqrt{x} \big) }{\big( \sqrt{x} \big) ^2}[/tex]
  3. Derivative Rule [Product Rule]:                                                                   [tex]\displaystyle F'(x) = \frac{\sqrt{x} \Big[ \big( x \big) '- \big( (5x)' \sqrt{x} + 5x(\sqrt{x})' \big) \Big] - \big( \sqrt{x} \big) ' \big( x - 5x\sqrt{x} \big) }{\big( \sqrt{x} \big) ^2}[/tex]
  4. Rewrite [Derivative Rule - Multiplied Constant]:                                        [tex]\displaystyle F'(x) = \frac{\sqrt{x} \Big[ \big( x \big) '- \big( 5(x)' \sqrt{x} + 5x(\sqrt{x})' \big) \Big] - \big( \sqrt{x} \big) ' \big( x - 5x\sqrt{x} \big) }{\big( \sqrt{x} \big) ^2}[/tex]
  5. Derivative Rule [Basic Power Rule]:                                                            [tex]\displaystyle F'(x) = \frac{\sqrt{x} \Big[ 1 - \big( 5\sqrt{x} + \frac{5x}{2\sqrt{x}} \big) \Big] - \frac{1}{2\sqrt{x}} \big( x - 5x\sqrt{x} \big) }{\big( \sqrt{x} \big) ^2}[/tex]
  6. Simplify:                                                                                                        [tex]\displaystyle F'(x) = \frac{\sqrt{x} \Big( 1 - 5\sqrt{x} - \frac{5x}{2\sqrt{x}} \Big) - \frac{x}{2\sqrt{x}} + \frac{5x\sqrt{x}}{2\sqrt{x}}}{x}[/tex]
  7. Simplify:                                                                                                        [tex]\displaystyle F'(x) = \frac{\sqrt{x} - 5x - \frac{5x}{2} - \frac{x}{2\sqrt{x}} + \frac{5x}{2}}{x}[/tex]
  8. Simplify:                                                                                                        [tex]\displaystyle F'(x) = \frac{\frac{\sqrt{x}}{2} - 5x}{x}[/tex]
  9. Simplify:                                                                                                        [tex]\displaystyle F'(x) = \frac{- \Big( 10\sqrt{x} - 1 \Big) }{2\sqrt{x}}[/tex]
  10. Rewrite:                                                                                                         [tex]\displaystyle F'(x) = \frac{1}{2\sqrt{x}} - 5[/tex]

∴ we find the derivative of the given function but it is a tedious method of computation.

Step 3: Differentiate Way 2

  1. [Function] Rewrite:                                                                                       [tex]\displaystyle F(x) = \frac{x}{\sqrt{x}} - \frac{5x\sqrt{x}}{\sqrt{x}}[/tex]
  2. [Function] Simplify:                                                                                       [tex]\displaystyle F(x) = \sqrt{x} - 5x[/tex]
  3. [Derivative] Rewrite [Derivative Property - Addition/Subtraction]:           [tex]\displaystyle F'(x) = \big( \sqrt{x} \big) ' - \big( 5x \big) '[/tex]
  4. Rewrite [Derivative Property - Multiplied Constant]:                                 [tex]\displaystyle F'(x) = \big( \sqrt{x} \big) ' - 5 \big( x \big) '[/tex]
  5. Derivative Rule [Basic Power Rule]:                                                            [tex]\displaystyle F'(x) = \frac{1}{2\sqrt{x}} - 5[/tex]

∴ we find the derivative of the given function and it is less complex and faster. We can conclude that simplifying first appears to be simpler for this problem.

---

Learn more about differentiation: https://brainly.com/question/17830594

Learn more about calculus: https://brainly.com/question/23558817

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation