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Sagot :

Given :

  • Length of the rectangle is [tex] \sf \: 2 \dfrac{4}{5} mm[/tex]

  • Breadth of the rectangle is [tex] \sf \: 2\dfrac{3}{7} \: mm[/tex]

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To Find :

  • The area of the rectangle.

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Solution :

We know that,

[tex]\qquad \pmb{\bf{Area_{(Rectangle)}= Length \times width }}[/tex]

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So, Substituting the given values :

[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = 2 \dfrac{4}{5} \times 2 \dfrac{3}{7} }}[/tex]

[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{14}{5} \times \dfrac{17}{7} }}[/tex]

[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{ \cancel{14}}{5} \times \dfrac{17}{ \cancel{7}} }}[/tex]

[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{2}{5} \times {17} }}[/tex]

[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{34}{5} }}[/tex]

[tex] \: \qquad \dashrightarrow \sf{{Area _{(Rectangle)} = 6 \dfrac{4}{5} \: {mm}^{2} }}[/tex]

Therefore,

  • Area of the rectangle is [tex] \sf6 \dfrac{4}{5} \: {mm}^{2} [/tex]
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