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using the right triangle
Find the value of x'
13
X
12


Using The Right Triangle Find The Value Of X 13 X 12 class=

Sagot :

Answer:

5

Step-by-step explanation:

Apply Pythagorean theorem

[tex]13 {}^{2} = 12 {}^{2} + x {}^{2} \\ 169 = 144 + x {}^{2} \\ x {}^{2} = 169 - 144 \\ x {}^{2} = 25 \\ x = \sqrt{25} \\ x = 5[/tex]

Answer:

A. [tex]\displaystyle 5[/tex]

Step-by-step explanation:

Use the Pythagorean Theorem:

[tex]\displaystyle a^2 + b^2 = c^2 \\ \\ 12^2 + b^2 = 13^2 \hookrightarrow 144 + b^2 = 169 \hookrightarrow \sqrt{25} = \sqrt{b^2} \\ \\ \boxed{5 = b}[/tex]

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