Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

A bouncy ball is dropped such that the height of its first bounce is 3.25 feet and each successive bounce is 71% of the previous bounce's height. What would be the height of the 7th bounce of the ball? Round to the nearest tenth (if necessary).

Sagot :

Using a geometric sequence, it is found that the height of the 7th bounce of the ball would be of 0.4 feet.

What is a geometric sequence?

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

[tex]a_n = a_1q^{n-1}[/tex]

In which [tex]a_1[/tex] is the first term.

In this problem, the first bounce is 3.25 feet and each successive bounce is 71% of the previous bounce's height, hence the first term and the common ratio are given, respectively, by:

[tex]a_1 = 3.25, q = 0.71[/tex]

Hence, the height of the nth bounce is given by:

[tex]a_n = 3.25(0.71)^{n-1}[/tex]

Then, the height of the 7th bounce in feet is of:

[tex]a_7 = 3.25(0.71)^6 = 0.4[/tex]

More can be learned about geometric sequences at https://brainly.com/question/11847927

#SPJ1

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.