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The width of a rectangle is 7 less than the length. If the perimeter of the rectangle is 43.6 inches, what is the area of the rectangle?

Sagot :

Aisin

Call the length a, the width b

Perimeter = (a+b) x 2

And since we have (a+b) x 2 = 43.6, a + b = 43.6 : 2 = 21.8

a + b = 21.8
a - b = 7

-> a + b + (a - b) = 28.8
2a = 28.8
a = 14.4
b = 7.4

So, the area of the rectangle is 14.4 x 7.4 = 106.56

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