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Sagot :
volume of the composite figure = volume of cylinder - volume of cone
volume of cylinder = πr²h
[tex] \frac{22}{7} \times 8 \times 8 \times 12 \\ \\ = > \frac{16896}{7} \: ft {}^{3} [/tex]
volume of cone = 1/3 πr²h
[tex] \frac{1}{3} \times \frac{22}{7} \times 8 \times 8 \times 12 \\ \\ = > \frac{16896}{21} \: ft {}^{3} [/tex]
[tex]total \: volume = \frac{16896}{7} - \frac{16896}{21} \\ \\ = > \frac{50688 - 16896}{21} \\ \\ = > \frac{33792}{21} \\ \\ = > 1609.14 \: ft {}^{3} (approx.)[/tex]
hope helpful~
Answer:
[tex]\large\boxed{\sf\: Volume \: of \: the \: figure\: \approx \: 1607.68\: feet^{3}}[/tex]
Step-by-step explanation:
We need to find the volume of each composite figure given in the question. Here, the figures are ⟶ a cylinder & a cone.
Given,
- Radius (r) = 8 feet
- Height (h) = 12 feet
- Take the value of π = 3.14
NOTE: The values of the radius & the height of both the figures remain the same as the cone is fit inside the cylinder.
The formulae of the volume of the figures are [tex]\downarrow[/tex]
- Cylinder = πr²h
- Cone = ⅓ πr²h
So,
Volume of cylinder
= πr²h
= 3.14 × (8)² × 12
= 2,411.52 feet³ (approx.)
Volume of cone
= ⅓ πr²h
= ⅓ × Volume of cylinder
= ⅓ × 2,411.52
= 803.84 feet³ (approx.)
Thus, the total volume of the figure
= Volume of cylinder - Volume of the cone
= 2,411.52 - 803.84
= 1,607.68 feet³ (approx.)
•°• Total volume of the composite figure = 1,607.68 feet³ (approx)
_______________
Hope this helps!
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