202101083
Answered

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Answer:

[tex]\sf y=7\frac{2}{3}[/tex] and [tex]\sf x = \frac{2}{3}[/tex]

Explanation:

[tex]\sf (1) \ \ (2x+y = 9)[/tex]

[tex]\sf (1) \ \ (2x+5y = 37)[/tex]

solve for y:

[tex]\sf 2x + y = 9[/tex]

[tex]\sf 2x + 5y = 37[/tex]

-----------------

[tex]\sf 0x + 6y = 46[/tex]

[tex]\sf 6y = 46[/tex]

[tex]\sf y=\frac{23}{3}[/tex]

[tex]\sf y=7\frac{2}{3}[/tex]

solve for x:

[tex]\sf 2x + y = 9[/tex]

[tex]\sf 2x = 9 - y[/tex]

[tex]\sf 2x = 9 - \frac{23}{3}[/tex]

[tex]\sf 2x = \frac{4}{3}[/tex]

[tex]\sf x = \frac{2}{3}[/tex]

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