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find the funcation rule for thr line that passes throught thr orgin 0,0 and the poiny (-9,19) what is the function rule for the line

Sagot :

fieryanswererft

Answer:

[tex]\sf y = -2\frac{1}{9} x[/tex]

linear function solve:

coordinates given: (0,0), (-9,19)

slope:

[tex]\sf \frac{y2-y1}{x2-x1}[/tex]

[tex]\sf \frac{19-0}{-9-0}[/tex]

[tex]\sf \frac{19}{-9}[/tex]

equation:

[tex]\sf y - y_2 = m(x-x_2 )[/tex]

[tex]\sf y - 0 = \frac{19}{-9} (x-0 )[/tex]

[tex]\sf y = \frac{19}{-9} x[/tex]

[tex]\sf y = -2\frac{1}{9} x[/tex]

semsee45

Answer:

[tex]f(x)=-\dfrac{19}{9}x[/tex]

Step-by-step explanation:

Let [tex](x_1,y_1)[/tex] = (0, 0)

Let [tex](x_2,y_2)[/tex] = (-9, 19)

First find the slope of the function using [tex]\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\implies \textsf{slope }m=\dfrac{19-0}{-9-0}=-\dfrac{19}{9}[/tex]

Now use the point-slope form of a linear equation: [tex]y-y_1=m(x-x_1)[/tex]

[tex]\implies y-19=-\dfrac{19}{9}(x+9)[/tex]

[tex]\implies y=-\dfrac{19}{9}x[/tex]

[tex]\implies f(x)=-\dfrac{19}{9}x[/tex]

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