dave4963
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

find how the circles x^2+y^2+2x+6y=39 and x^2+y^2-4x-2y+1=0​

Sagot :

ganjilaya2019

Step-by-step explanation:

x² + y² + 2x + 6y = 39

( x + 1)² - 1 + ( y + 3)² - 9 = 39

( x + 1)² + ( y + 3)² - 10 = 39

(x + 1)² + (y + 3)² = 49

radius= √49 = 7

center = ( -1 , -3)

x² + y² - 4x - 2y + 1 = 0

(x - 2)² - 4 + (y - 1)² -1 + 1 = 0

(x - 2)² + (y - 1)² = 4

radius = √4 = 2

center = (2 , 1)

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.